Requête SQL pour les combinaisons sans répétition


22

J'ai besoin d'une requête qui peut être utilisée dans (ou comme) une fonction et récupère toutes les combinaisons de n valeurs. Et j'ai besoin de toutes les combinaisons de longueur k où k = 1..n.

Entrée et résultat d'échantillon étendus pour que l'entrée ait 3 valeurs au lieu de 2 - cependant, le nombre de valeurs d'entrée peut varier de 1 à n.

Exemple: entrée: table avec des valeurs dans une colonne sur plusieurs lignes

Value  (nvarchar(500))
------
Ann
John
Mark

Résultat n ° 1: tableau avec valeurs concaténées dans une colonne

    Ann
    John
    Mark
    Ann,John
    John,Mark
    Ann,Mark
    Ann,John,Mark

Réponses:


36

Pour des valeurs relativement petites de n(20 dans cet exemple), vous pouvez utiliser une méthode qui exploite le fait que les entiers naturels sont des combinaisons de bits.

Solution T-SQL

Exemples de données:

DECLARE @Sample AS TABLE 
(
    item_id     tinyint IDENTITY(1,1) PRIMARY KEY NONCLUSTERED,
    item        nvarchar(500) NOT NULL,
    bit_value   AS 
                CONVERT
                (
                    integer, 
                    POWER(2, item_id - 1)
                )
                PERSISTED UNIQUE CLUSTERED
);    

INSERT @Sample
    (item)
VALUES
    (N'Ann'),
    (N'Bob'),
    (N'Charles'),
    (N'Darren'),
    (N'Eric'),
    (N'Fred'),
    (N'George'),
    (N'Harry'),
    (N'Ian'),
    (N'John'),
    (N'Keith'),
    (N'Larry'),
    (N'Mark'),
    (N'Nathan'),
    (N'Owen'),
    (N'Paul'),
    (N'Quentin'),
    (N'Ryan'),
    (N'Steve'),
    (N'Terry');

Solution:

-- Maximum integer we need
-- for all combinations of 'n' bits
DECLARE 
    @max integer = 
    POWER(2,
        (
            SELECT COUNT(*) 
            FROM @Sample AS s
        )
    ) - 1;

SELECT
    combination =
        STUFF
        (
            (
                -- Choose items where the bit is set
                -- and concatenate all matches
                SELECT ',' + s.item 
                FROM @Sample AS s
                WHERE
                    n.n & s.bit_value = s.bit_value
                ORDER BY
                    s.bit_value
                FOR XML 
                    PATH (''),
                    TYPE                    
            ).value('(./text())[1]', 'varchar(8000)'), 1, 1, ''
        )
-- A standard numbers table
-- (single column, integers from 1 to 1048576, indexed)
FROM dbo.Numbers AS N
WHERE
    N.n BETWEEN 1 AND @max;

Échantillon de sortie:

╔════════════════════════╗
      combination       
╠════════════════════════╣
 Ann                    
 Bob                    
 Ann,Bob                
 Charles                
 Ann,Charles            
 Bob,Charles            
 Ann,Bob,Charles        
 Darren                 
 Ann,Darren             
 Bob,Darren             
 Ann,Bob,Darren         
 Charles,Darren         
 Ann,Charles,Darren     
 Bob,Charles,Darren     
 Ann,Bob,Charles,Darren 
 ...                    
╚════════════════════════╝

Plan d'exécution:

Plan d'exécution

Il faut 41 secondes pour écrire les 1 048 576 combinaisons dans une variable de mon ordinateur portable. Avec le parallélisme forcé, j'ai pu réduire le temps d'exécution DOP 8à 13 secondes.

Si vous avez besoin d'une table Numbers, c'est un moyen rapide d'en produire une:

SELECT TOP (1048576)
    n = ISNULL(CONVERT(integer, ROW_NUMBER() OVER (ORDER BY (SELECT NULL))), 0)
INTO dbo.Numbers
FROM sys.columns AS c
CROSS JOIN sys.columns AS c2
CROSS JOIN sys.columns AS c3;

CREATE UNIQUE CLUSTERED INDEX cuq
ON dbo.Numbers (n)
WITH (MAXDOP = 1, SORT_IN_TEMPDB = ON);

Solution SQLCLR

Une implémentation beaucoup plus efficace est possible dans SQLCLR (SQL Server 2005 et suivants):

CREATE ASSEMBLY [Demo]
    AUTHORIZATION [dbo]
    FROM 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GO
CREATE FUNCTION dbo.Combinations
(
    @ElementsCSV nvarchar (4000)
)
RETURNS TABLE
(
    Combination nvarchar (4000) NULL
)
AS EXTERNAL NAME Demo.UserDefinedFunctions.Permute;

Exemple d'utilisation:

SELECT 
    f.Combination
FROM dbo.Combinations('A,B,C,D') AS f;

Sortie:

╔═════════════╗
 Combination 
╠═════════════╣
 A           
 B           
 A,B         
 C           
 A,C         
 B,C         
 A,B,C       
 D           
 A,D         
 B,D         
 A,B,D       
 C,D         
 A,C,D       
 B,C,D       
 A,B,C,D     
╚═════════════╝

En utilisant l'ensemble de 20 éléments du précédent:

DECLARE @Sample AS TABLE 
(
    item_id     tinyint IDENTITY(1,1) PRIMARY KEY CLUSTERED,
    item        nvarchar(50) NOT NULL
);

INSERT @Sample
    (item)
VALUES
    (N'Ann'),
    (N'Bob'),
    (N'Charles'),
    (N'Darren'),
    (N'Eric'),
    (N'Fred'),
    (N'George'),
    (N'Harry'),
    (N'Ian'),
    (N'John'),
    (N'Keith'),
    (N'Larry'),
    (N'Mark'),
    (N'Nathan'),
    (N'Owen'),
    (N'Paul'),
    (N'Quentin'),
    (N'Ryan'),
    (N'Steve'),
    (N'Terry');

Solution SQLCLR:

-- Create CSV input
DECLARE 
    @Elements nvarchar(4000) =
        STUFF
        (
            (
                SELECT ',' + s.item 
                FROM @Sample AS s
                ORDER BY
                    s.item_id
                FOR XML 
                    PATH (''),
                    TYPE                    
            ).value('(./text())[1]', 'varchar(8000)'), 1, 1, ''
        );

DECLARE
    @bitbucket nvarchar(4000);

SELECT
    @bitbucket = combination
FROM dbo.Combinations(@Elements);

Le temps d'exécution est de 2,5 secondes pour les 1 048 576 combinaisons sur mon ordinateur portable à DOP 1.

Création de l'entrée CSV:

Plan d'entrée CSV

Trouver les combinaisons:

Plan de fonction SQLCLR

Code source C #:

using System;
using System.Collections;
using Microsoft.SqlServer.Server;

public partial class UserDefinedFunctions
{
    [SqlFunction
        (
        DataAccess=DataAccessKind.None, 
        SystemDataAccess=SystemDataAccessKind.None,
        FillRowMethodName="FillRow",
        TableDefinition="Permutation nvarchar(4000)"
        )
    ]
    public static IEnumerable Permute(string ElementsCSV)
    {
        // Split CSV
        string[] elements = ElementsCSV.Split(new char[] { ',' });

        // Highest integer needed
        int count = (int)Math.Pow(2, elements.Length) - 1;

        // Pre-computed array of 2^n values
        int[] powers = new int[elements.Length];

        for (int i = 0; i < powers.Length; i++)
        {
            powers[i] = (int)Math.Pow(2, i);
        }

        // Test integers
        for (int i = 1; i <= count; i++)
        {
            // Reset output
            string s = string.Empty;

            // Test each bit that could be set
            for (int bit = 0; bit < powers.Length && i >= powers[bit]; bit++)
            {
                if ((i & powers[bit]) == powers[bit])
                {
                    // Add the element corresponding to the set bit
                    s += elements[bit] + ',';
                }
            }

            // Return a row via enumeration
            yield return s.Substring(0, s.Length - 1);
        }
    }

    // Called by SQL Server to fetch a row
    public static void FillRow(object o, out string Permutation)
    {
        Permutation = (string)o;
    }
}
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